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current electricity
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TOPIC: current electricity
#20730

current electricity 4 Years, 5 Months ago

 
A milliammeter of range 10mA & resistance 9Ω is joined in a circuit as shown in the fig. The meter gives full scale deflection for current I when A & B are used as its terminals , i.e., current enters at A & leaves at B (C left isolated).The value of I is a) 100mA b) 900mA c) 1A d) 1.1A



saurabh (User)
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#77095

Re: current electricity 4 Years ago

 
9 and 0.9 are in series w.r.to A and B and 0.1 is in parallel to this series combination. The total current is divided between these two branches in which one has total resistance as 9.9 and other has 0.1. Current I is divided into 10 mA in one branch and I-10 mA in other . SO 9.9 x 10 mA =( I -10 mA ) X 0.1. . Calclate I which will be in mA


Kajal Sengupta (User)
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#77107

Re: current electricity 4 Years ago

 
i thnk so answer is 100 mA wts d answer....? i solved it ..... tl me d ans

nupur (User)
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#95406

Re: current electricity 3 Years, 11 Months ago

 

0.1 mili ampere.....



abhimanyu raj (User)
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#95458

Re: current electricity 3 Years, 11 Months ago

 
ans is coming 1A......@sourabh, plss give the right answer.........as soon as possible..

NABARUN RAHA (User)
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#96549

Re: current electricity 3 Years, 11 Months ago

 

Dear...

Question is very simple

..

See  specification of ammerter is  9 ohm and 10 mA

That means it can have maximum current 10 mA with it

So from I which enters through A ...10 mA will goes through Ammeter and then 0.9 ohm resistance and finallt leave through terminal B

Also the net current (I-10) will pass through resistance 0.1 ohm and leave from B

SO final current entering A is I  and leaving b is (I-10)+10

So The potential accross AB will be equal to potential accros terminal of Ammeter and accross resistance 0.9 ohm

So aply equation

9(10mA) + 0.9(10mA)  = (I-10)mA ( 0.1)

99  = (0.1* I - 1 )

so  0.1*I = 100

or I = 1000 mA

or I = 1 A

Note : for furthure doutb ask !

Good wishes



Yagya Dutt Mishra (User)
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Yagya Dutt Mishra
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